0=-16t^2+12t+10

Solution for 0=-16t^2+12t+10 equation:

0=-16t^2+12t+10

We move all terms to the left:

0-(-16t^2+12t+10)=0

We add all the numbers together, and all the variables

-(-16t^2+12t+10)=0

We get rid of parentheses

16t^2-12t-10=0

a = 16; b = -12; c = -10;
Δ = b2-4ac
Δ = -122-4·16·(-10)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-28}{2*16}=\frac{-16}{32}
=-1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+28}{2*16}=\frac{40}{32}
=1+1/4
$